2x^2-51x-270=0

Solution for 2x^2-51x-270=0 equation:

2x^2-51x-270=0

a = 2; b = -51; c = -270;
Δ = b2-4ac
Δ = -512-4·2·(-270)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-69}{2*2}=\frac{-18}{4}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+69}{2*2}=\frac{120}{4}
=30
$